here is the list of expressions i put in

sinx(1+cosx)/(1-cosx)(1+cosx)

sinx(1+cosx)/1-cos^2 x

sinx(1+cosx)/sin^2 x

1+cosx/sinx

1/sinx + cosx/sinx

Guest Apr 20, 2020

#1**+1 **

We want csc x + cot x to get into terms of sin and cos, that means the first box that you drag in is 1/sinx + cosx/sinx as this is the first step that you could possibly take. They have the same base so we can combine it to be (1+cosx)/sinx. We then multiply the function by sinx/sinx which turns the denominator into sin^2x which is also (1-cos^2x), so right now the function is (sinx(cosx))/(1-cos^2x). We can then break the denominator into two pieces by difference of squares, so we have (sinx(1+cosx))/((1+cosx)(1-cosx)). the (1+cosx) in both the numerator and denominator cancel out and we are left with the identity.

arism Apr 20, 2020