+386 Hi there!
I have log(a)=x
I need to come up with an equation with only "x" as a variable.
This equation must = log ( (1000(square root of (a^3) ) ) /a^-1)
I've done the following:
If log(a) = x then a = 10^x
log ( (1000(square root of (a^3) ) ) /a^-1) = log ( (1000(square root of ( (10^x)^3) ) ) /(10^x)^-1)
= log ( (1000( (10^x)^3/2) ) ) /(10^x)^-1)
= log ( (1000( 10^3/2x ) ) /10^-1x)
= ( log 1000 (log (10^3/2x) ) ) / log (10^-1x)
= (3 (1^3/2x) ) / 1^-1x)
I can't seem to find where I have gone wrong. When I try to verify with x=2 :
(3 (1^3/2x) ) / 1^-1x) = 3 (obviously) and log ( (1000(square root of ( (10^x)^3) ) ) /(10^x)^-1) = 8
Help!
You must know beforehand what the result is in order to solve for x. This expression:
log ( (1000(square root of ( (10^x)^3) ) ) /(10^x)^-1)=?. In other words:? must equal something!!.
+386 Well I swear it's the only information I have. This is part of a work for my math class. This was verified by my professor and he says that it is possible to find an answer with these information.
... meh I'm quite puzzled to!
Well, you can specify what x equals beforehand and you will get an answer. You can also have the expression equal to another variable such as "a". Then you can solve for x in terms of "a".
If you set it up to =a, for example, then you will have this solution:
log ( (1000(square root of ( (10^x)^3) ) ) /(10^x)^-1)=a, solve for x
x = (2 (a - 3))/5
+386 Ok but what I need is to make an equation that has only x as a variable that will =
log ( (1000 (square root of (A^3) ) ) / A^-1 )
Cause right now if we solve in terms of "a", like you said, wouldn't it leave me with a new undefined variable?
like that "a" would be = the equation with only "x" as variable that is needed.
