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# Vertical Asymptotes of Limit approaching 0

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The function in the problem is $$f(x)= (8/x^3)-(6/x)$$

We have to find any vertical asymptotes of the graph. Based on the function itself, and a graph, I can tell there is a vertical asymptote at x=0, and that each one sided limit of x=0 is respectively infinite and negative infinite.

But, I was told to find the vertical asymptote by using a limit, since that is how the AP Calc test wants the work done.

I might just be having a brain f**t right now, but how do I evaluate $$lim(x\rightarrow0^+)((8/x^3)-(6/x))$$ or $$lim(x\rightarrow0^-)((8/x^3)-(6/x))$$ without just substituting and getting the limit equals 0?

Also this is a no calculator question.

Thanks

Guest Mar 2, 2018
edited by Guest  Mar 2, 2018
edited by Guest  Mar 2, 2018
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Hi

if you still need help with this just leave a message here and i'll get back to you

cheers

Guest Mar 6, 2018

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