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What is the greatest whole number that must be a divisor of the product of any three consecutive positive integers?

 Jul 27, 2020
 #1
avatar+146 
+1

I think the answer should be 6.

In every three consecutive integers, one of them must be a multiple of three. And there must be at least one multiple of two as well. So 3 x 2 = 6.

 

I hope this helped.

 Jul 27, 2020
 #4
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Thx!

Swim2433  Jul 27, 2020
 #2
avatar+26856 
+2

I suppose 6?

 

1 x 2 x 3 = 6

2 x 3 x 4

3 x 4 x 5

4 5 6

 Jul 27, 2020
 #3
avatar+83 
0

Thx!

Swim2433  Jul 27, 2020

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