+9481 \(\frac{2n^2}{2n} \\~\\ =\frac{2\,\cdot \, n\,\cdot \, n}{2\,\cdot\, n}\)
The 2's in the numerator and denominator cancel.
\(=\frac{\not2\,\cdot \, n\,\cdot \, n}{\not2\,\cdot\, n} \\~\\ =\frac{n\,\cdot \, n}{n}\)
The n's in the numerator and denominator cancel.
\(=\frac{n\,\cdot\, \not{n}}{\not{n}} \\~\\ =n\)
(Also, when we canceled the n from the denominator we should say n ≠ 0 )
+9481 \(\frac{2n^2}{2n} \\~\\ =\frac{2\,\cdot \, n\,\cdot \, n}{2\,\cdot\, n}\)
The 2's in the numerator and denominator cancel.
\(=\frac{\not2\,\cdot \, n\,\cdot \, n}{\not2\,\cdot\, n} \\~\\ =\frac{n\,\cdot \, n}{n}\)
The n's in the numerator and denominator cancel.
\(=\frac{n\,\cdot\, \not{n}}{\not{n}} \\~\\ =n\)
(Also, when we canceled the n from the denominator we should say n ≠ 0 )
+129952
Guest.....you are just dividing "horizontally"......in essence, hectictar is doing the very same thing in a "fraction" form
10 and 10 / 2 are exactly the same thing....
2
+42 for some reason im answering a rational equation right now
in rational equation, you have to find the LCD right? for example the LCD was = 2n^2
the equation was :
n-6/2n
so the first thing to do is to divide the LCD to denominator
so it will end up like : 2n^2 divide 2n
Now my problem is how do i divide 2n^2 to 2n?
the possible anser be like : 2n or 2?
now it would look like : 2n(n-6) or 2(n-6)
I hope it is now clearer than before :D
btw tnx for you guys hardwork :)
+9481 n - 6/2n
Is this the problem?
If it is..it that exactly how it is written? Or is it
n - 6/(2n)
? 
+9481 If this is exactly as the question is written...
(n - 6) / (2n)
This is also
= n / (2n) - 6 / (2n)
We can reduce the first fraction by n .
= 1 / 2 - 6 / (2n)
We can reduce the second fraction by 2.
= 1 / 2 - 3 / n
..........
I don't really know what you mean by " divide the LCD " . Why do you want to divide the LCD ?
Is that what the instructions tell you to do?
Maybe the problem is
n - 6 / (2n) ?
Reduce the second fraction by 2.
= n - 3/n
We can get the LCD by multiplying the first term by n/n ,
which gives us
= n2 / n - 3 / n
= (n2 - 3) / n
....
BTW, I see you became a member! Welcome aboard!
+42 Sorry for late reply i'm just having a mini break lately xD
i think you're right and yeah my intructor told me to do that..
Does in prime factorization also have "dividing LCD thing?" just our topic lately.
maybe i mistaken it for rational equation?
idk why but i can't just tell her about this lol
i'm actually having a summer tutorial in math tho
now with some bunch of paperworks..
Btw. thanks for help! it helped a TON!!
