#1**+3 **

\(\frac{2n^2}{2n} \\~\\ =\frac{2\,\cdot \, n\,\cdot \, n}{2\,\cdot\, n}\)

The 2's in the numerator and denominator cancel.

\(=\frac{\not2\,\cdot \, n\,\cdot \, n}{\not2\,\cdot\, n} \\~\\ =\frac{n\,\cdot \, n}{n}\)

The n's in the numerator and denominator cancel.

\(=\frac{n\,\cdot\, \not{n}}{\not{n}} \\~\\ =n\)

(Also, when we canceled the n from the denominator we should say n ≠ 0 )

hectictar
Jun 1, 2017

#1**+3 **

Best Answer

\(\frac{2n^2}{2n} \\~\\ =\frac{2\,\cdot \, n\,\cdot \, n}{2\,\cdot\, n}\)

The 2's in the numerator and denominator cancel.

\(=\frac{\not2\,\cdot \, n\,\cdot \, n}{\not2\,\cdot\, n} \\~\\ =\frac{n\,\cdot \, n}{n}\)

The n's in the numerator and denominator cancel.

\(=\frac{n\,\cdot\, \not{n}}{\not{n}} \\~\\ =n\)

(Also, when we canceled the n from the denominator we should say n ≠ 0 )

hectictar
Jun 1, 2017

#3**+2 **

Guest.....you are just dividing "horizontally"......in essence, hectictar is doing the very same thing in a "fraction" form

__10__ and 10 / 2 are exactly the same thing....

2

CPhill
Jun 1, 2017

#4**+1 **

for some reason im answering a rational equation right now

in rational equation, you have to find the LCD right? for example the LCD was = 2n^2

the equation was :

n-6/2n

so the first thing to do is to divide the LCD to denominator

so it will end up like : 2n^2 divide 2n

Now my problem is how do i divide 2n^2 to 2n?

the possible anser be like : 2n or 2?

now it would look like : 2n(n-6) or 2(n-6)

I hope it is now clearer than before :D

btw tnx for you guys hardwork :)

Virax1o1
Jun 1, 2017

#6**+2 **

n - 6/2n

Is this the problem?

If it is..it that exactly how it is written? Or is it

n - 6/(2n)

?

hectictar
Jun 1, 2017

#8**+5 **

If this is exactly as the question is written...

(n - 6) / (2n)

This is also

= n / (2n) - 6 / (2n)

We can reduce the first fraction by n .

= 1 / 2 - 6 / (2n)

We can reduce the second fraction by 2.

= 1 / 2 - 3 / n

..........

I don't really know what you mean by " divide the LCD " . Why do you want to divide the LCD ?

Is that what the instructions tell you to do?

Maybe the problem is

n - 6 / (2n) ?

Reduce the second fraction by 2.

= n - 3/n

We can get the LCD by multiplying the first term by n/n ,

which gives us

= n^{2} / n - 3 / n

= (n^{2} - 3) / n

....

BTW, I see you became a member! Welcome aboard!

hectictar
Jun 1, 2017

#9**+2 **

Sorry for late reply i'm just having a mini break lately xD

i think you're right and yeah my intructor told me to do that..

Does in prime factorization also have "dividing LCD thing?" just our topic lately.

maybe i mistaken it for rational equation?

idk why but i can't just tell her about this lol

i'm actually having a summer tutorial in math tho

now with some bunch of paperworks..

Btw. thanks for help! it helped a TON!!

Virax1o1
Jun 1, 2017