find (1+r) (1+s) (1+t) (1+u )if r,s,t,y are the roots of f(x)=3x^4-x^3+2x^2+7x+2
Expanding (1+r)(1+s)(1+t)(1+u), we get: rstu+(rst+rsu+rtu+stu)+(rs+rt+ru+st+su+tu)+(r+s+t+u)+1
We can use Vieta's to get: rstu=2/3,rst+rsu+rtu+stu=−7/3,rs+rt+ru+st+su+tu=2/3,r+s+t+u=1/3
Adding, we get 2/3−7/3+2/3+1/3+1=1/3