Find all values of x where there is a vertical asymptote for the equation y=x+1x2−2x+1.
+355 From what I can gather (my LaTeX is hot garbage) your equation is:
y=(x+1)/(x^2-2x+1)
f(x)=y (i think im kinda rusty)
x=L is a vertical asymptote of f(x)=(x+1)/(x^2-2x+1), that is, if the limit of the function is infinite, to restate, it means that possible points are points where the denominator equals 0 or doesn't exist. *p**f*
So, just find the points where the denominator equals 0 and check them! Easy as pie!
x=1 chaching
x=1 is a vertical asymptote.
Yay!
