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# Waht, how?

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Find all values of x where there is a vertical asymptote for the equation $$y=\frac{x+1}{x^2-2x+1}$$.

Aug 16, 2020

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From what I can gather (my LaTeX is hot garbage) your equation is:

y=(x+1)/(x^2-2x+1)

f(x)=y (i think im kinda rusty)

x=L is a vertical asymptote of f(x)=(x+1)/(x^2-2x+1), that is, if the limit of the function is infinite, to restate, it means that possible points are points where the denominator equals 0 or doesn't exist. *p**f*

So, just find the points where the denominator equals 0 and check them! Easy as pie!

x=1 chaching

x=1 is a vertical asymptote.

Yay!

Aug 16, 2020