Solve the system of equations using the substitution method. I can't understand the 5/6x!!

y = 2 + 5/6 * x 4x - 3y = 3

Guest Dec 16, 2019

#1**0 **

\(\mathrm{Subsititute\:}y=2+\frac{5}{6}\cdot \:x \)

\(\begin{bmatrix}4x-3\left(2+\frac{5}{6}x\right)=3\end{bmatrix}\)

\(\mathrm{Isolate}\:x\:\mathrm{for}\:4x-3\left(2+\frac{5}{6}x\right)=3:\quad x=6\)

\(\mathrm{For\:}y=2+\frac{5}{6}\cdot \:x\)

\(\mathrm{Subsititute\:}x=6\)

\(2+\frac{5}{6}\cdot \:6=7\)

\(y=7, \text{Solution is x=6, y=7}\)

.whoisjoe Dec 16, 2019

#2**0 **

~~y = 2 + 20/6 x - 3y add 3 y to both sides of the equation~~

~~4y = 2 + (20/6) x your original Q says y = 3 substitute that in~~

~~12 = 2 + 20/6 x subtract 2 from both sides~~

~~10 = 20/6 x multiply both sides by 6/20~~

~~60/20 = x = 3~~

Now I see your question has TWO Equations....please put some spaces in there !

y = 2 + 5/6 * x

4x - 3y = 3 Is much more clear.....see whoisjoe answer below....

ElectricPavlov Dec 16, 2019

#4**0 **

Hmm. We seem to be disagreeing. I think you forgot that y = 2 + 5/6x is a different term than 4x-3y=3, lol. Guest probably should have put something to tell us that they are 2 different terms, unless I am the mistaken one. Oh I see you didn't see that it was a system of equations so you just solved for x!

whoisjoe
Dec 16, 2019