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What are the intervals where f(x) is increasing and decreasing: f(x)=\(\frac{x}{\sqrt{x^2+1}}\)

 

What are local max/mins, and where is it concave up and down??

 Apr 4, 2016
edited by Guest  Apr 4, 2016
edited by Guest  Apr 4, 2016
edited by Guest  Apr 4, 2016
 #1
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Intervals increasing : (-infinity, infinity) 

Intervals decreasing: none 

local max : none

local min : none 

no local max/min because f(x) is always increasing 

intervals concave up : (-infinity, 0)

intervals concave down: (0, infinity) 

 Apr 4, 2016
 #2
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0

Fantastic, those are the same answers I just came up with.. So that's comforting haha :) thank you!

gretzu  Apr 4, 2016

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