what are the points of discontinuity? are they all removable? y= (x-5) / x^2 - 6x + 5
Note......
(x - 5) / [ x^2 - 6x + 5] =
(x - 5) / [ (x - 1) (x -5) ] =
1 / (x - 1)
There will be a "hole" at x = 5......but the discontinuity at x = 1 isn't "removable".....there's a vertical asymptote at that point......
Here's the graph.......
https://www.desmos.com/calculator/m598ibdrql
{Believe me....there is a "hole" at x = 5 !!!}
Note......
(x - 5) / [ x^2 - 6x + 5] =
(x - 5) / [ (x - 1) (x -5) ] =
1 / (x - 1)
There will be a "hole" at x = 5......but the discontinuity at x = 1 isn't "removable".....there's a vertical asymptote at that point......
Here's the graph.......
https://www.desmos.com/calculator/m598ibdrql
{Believe me....there is a "hole" at x = 5 !!!}