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# What are the solutions to the system of conics

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I finsished my entire quiz, I am stuck on the last question....I would really appreciate it if someone could help me solve this.

(PLEASE DO NOT REPLY IF YOU ARE NOT ANSWERING IT) Jan 5, 2020
edited by Beanpole  Jan 5, 2020

#1
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From the first equation:

x^2 -2 y^2 =4        (1)

the second equation tells ya what x^2  is equal to....substitute that value into (1)

4y + 8 -2y^2 = 4

2y^2 -4y - 4 = 0

y^2 -2y -2 = 0          Quadratic formula will tell you y = 1 + sqrt3   and  y = 1-sqrt3

Use these values of y ...sub into (1) and solve for x 's......That should get you started....

Jan 5, 2020

#1
+2

From the first equation:

x^2 -2 y^2 =4        (1)

the second equation tells ya what x^2  is equal to....substitute that value into (1)

4y + 8 -2y^2 = 4

2y^2 -4y - 4 = 0

y^2 -2y -2 = 0          Quadratic formula will tell you y = 1 + sqrt3   and  y = 1-sqrt3

Use these values of y ...sub into (1) and solve for x 's......That should get you started....

ElectricPavlov Jan 5, 2020