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# What did i do wrong in determining the sum for this geometric series?

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Here's the series: I took what I was given into the $$S_n = {a(1 - r^{n}) \over 1 - r}$$ formula where:

$${S_n}$$ is the sum of $${n}$$ number of terms

$${a}$$ is the first term

$${r}$$ is the common ratio

Here's my work:But I didn't get the answer, which is

I'm confused as to what did I do wrong?

Guest Jul 9, 2018
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Sum =6 x [1 - 3/2] / [1 - 3/2]

Sum =6 x [1 - 59,049 /1024] / [ - 1/2]

Sum =6 x [-58,025 /1,024] / [-1/2]

Sum =6 x [-58,015/1,024 x -2/1]

Sum =6 x [116,050/1,024]

Sum = 696,300 / 1,024       divide both sides by 4

Sum = 174,075 / 256

Guest Jul 9, 2018