#5**+10 **

Here's my understanding of it, Melody......

11 / 0 is "undefined" because we can't multiply anything by 0 in the denominator to return the "11" in the numerator

But.....consider......

0 / 0

We could multiply the denominator by * anything* to return the 0 in the numerator....thus....this is "indeterminate"....we can't determine exactly what this "thing" is......

It might be "pi"...it might be "10"....it might be "3.45612".......etc.

CPhill
May 14, 2015

#2**+5 **

To see why Melody's answer is true......consider the following where n is non-zero

0^{n} / 0^{n =}

0^{n-n =}

0^{0}

But....what's the problem???? .....Note that......in the fraction above, the denominator 0^{n} = 0 .....and we can't divide by 0.......

[It's actually more appropriate to term this situation, "indeterminate" ]

CPhill
May 14, 2015

#3**0 **

But that number * n *must be strictly greater than 0, because you can't have 0 to a power less than (or equal to) 0.

EinsteinJr
May 14, 2015

#4**+5 **

What is the difference between undefined and indeterminate Chris ?

Are they interchangable terms?

Melody
May 14, 2015

#5**+10 **

Best Answer

Here's my understanding of it, Melody......

11 / 0 is "undefined" because we can't multiply anything by 0 in the denominator to return the "11" in the numerator

But.....consider......

0 / 0

We could multiply the denominator by * anything* to return the 0 in the numerator....thus....this is "indeterminate"....we can't determine exactly what this "thing" is......

It might be "pi"...it might be "10"....it might be "3.45612".......etc.

CPhill
May 14, 2015