12canbewrittenas$121$,sonowwehave:$14−121$Theproblemhereisthatwedon′thaveacommondemoninator.Let′smultiply$121$by$44$togetacommondenominator.Wecandothisbecause$44$isreallythesamethingas1,andifyoumultiplyanynumberby1,youwillgetthatoriginalnumber.Forexample,$5×1=5$$99×1=99$,etc...So,let′smultiply$121$by$44$$14−(121×44)14−(484)−474$Andtherewego!ouransweris$−474$
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