what is 1190 divisible by

what is 1190 divisible by

$$\small{\text{
prime factorization: $ 1190 = 2^{\textcolor[rgb]{1,0,0}{1}}*5^{\textcolor[rgb]{0,1,0}{1}}*7^{\textcolor[rgb]{0,0,1}{1}}*17^{\textcolor[rgb]{0,1,1}{1}} $
}}$$

$$\small{\text{
The number of the divisors $ = (\textcolor[rgb]{1,0,0}{1} + 1)
*(\textcolor[rgb]{0,1,0}{1} + 1)
*(\textcolor[rgb]{0,0,1}{1} + 1)
*(\textcolor[rgb]{0,1,1}{1} + 1)
= 2*2*2*2 = 16$
}}$$

$$\begin{array}{|r|c|c|c|c|c|l|l|}
\hline
n & 1 & 2 & 5 & 7 & 17 & & devisor\\
\hline
1 & x & & & & & &= 1 \\
2 & & x & & & & &= 2 \\
3 & & & x & & & &= 5 \\
4 & & & & x & & &= 7 \\
5 & & & & & x & &=17 \\
6 & & x & x & & & 2*5 &= 10 \\
7 & & x & & x & & 2*7 &= 14 \\
8 & & x & & & x & 2*17 &= 34 \\
9 & & & x & x & & 5*7 &= 35 \\
10 & & & x & & x & 5*17 &= 85 \\
11 & & & & x & x & 7*17 &= 119 \\
12 & & x & x & x & & 2*5*7 &= 70 \\
13 & & x & x & & x & 2*5*17 &= 170 \\
14 & & x & & x & x & 2*7*17 &= 238 \\
15 & & & x & x & x & 5*7*17 &= 70 \\
16 & & x & x & x & x & 2*5*7*17 &= 1190 \\
\hline
\end{array}$$

Well, 1190 is divisible by a couple things.

1190 is divisible by 119 and 10.

1190 is also divisible by 17 and 70.