I'm guessing by "and" you mean addition?
In this case, we have to start by multiplying 2/7 by 3, then add that fraction to 4 and 1/2.
$${\mathtt{4}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{2}}}{{\mathtt{7}}}}{\mathtt{\,\times\,}}{\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{2}}}}$$
$${\mathtt{4}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{6}}}{{\mathtt{7}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{2}}}}$$
Multiply the top and bottom of the first fraction by 2. Multiply the top and bottom for the second fraction by 7.
$${\mathtt{4}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{12}}}{{\mathtt{14}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{7}}}{{\mathtt{14}}}}$$
$${\mathtt{4}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{19}}}{{\mathtt{14}}}}$$
$${\mathtt{4}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{5}}}{{\mathtt{14}}}}$$
$$5$ and $5/14$$
This can't be reduced, so it is our final answer.
Good job, ND...points and thumbs-up
I think the questioner may have also meant this:
(4 + 2/7 ) * ( 3 + 1/2) =
(30/7) * ( 7/2) cross-cancelling the "7s," we have
30/2 = 15