+0  
 
+5
758
6
avatar+831 

what is 4 and 2/7*3and1/2

 Jun 12, 2014

Best Answer 

 #3
avatar+129852 
+13

Good job, ND...points and thumbs-up

I think the questioner may have also meant this:

(4 + 2/7 )  * ( 3 + 1/2)  =

(30/7) * ( 7/2)      cross-cancelling the "7s," we have

30/2 =  15

 

 Jun 12, 2014
 #1
avatar+3454 
+10

I'm guessing by "and" you mean addition?

In this case, we have to start by multiplying 2/7 by 3, then add that fraction to 4 and 1/2.

 

$${\mathtt{4}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{2}}}{{\mathtt{7}}}}{\mathtt{\,\times\,}}{\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{2}}}}$$

$${\mathtt{4}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{6}}}{{\mathtt{7}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{2}}}}$$                 

Multiply the top and bottom of the first fraction by 2. Multiply the top and bottom for the second fraction by 7.

$${\mathtt{4}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{12}}}{{\mathtt{14}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{7}}}{{\mathtt{14}}}}$$

$${\mathtt{4}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{19}}}{{\mathtt{14}}}}$$

$${\mathtt{4}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{5}}}{{\mathtt{14}}}}$$

$$5$ and $5/14$$

 This can't be reduced, so it is our final answer.

 Jun 12, 2014
 #2
avatar+831 
+5

no i mean 4(2/7)*3(1/2)

 Jun 12, 2014
 #3
avatar+129852 
+13
Best Answer

Good job, ND...points and thumbs-up

I think the questioner may have also meant this:

(4 + 2/7 )  * ( 3 + 1/2)  =

(30/7) * ( 7/2)      cross-cancelling the "7s," we have

30/2 =  15

 

CPhill Jun 12, 2014
 #4
avatar+831 
+5

thnx i got it right thnx buddy

 Jun 12, 2014
 #5
avatar+3454 
+10

Oh yeah, CPhill's answer would make more sense.

I see my misinterpretation. :)

 Jun 12, 2014
 #6
avatar+129852 
0

NO ..  NO...  NO!!!  ....   NinjaDevo...you answered EXACTLY what was asked........

Your answer was actually more correct than MINE!!! I was answering an "assumed" question !!!  You applied the order of operations perfectly...

 

 Jun 12, 2014

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