To get an approximate answer, use logs:
x = 82015
---> log(x) = log(82015)
Since exponents in logs come out as multipliers:
---> log(x) = 2015·log(8) ≈ 1819.726
Find the antilog:
---> x = 101819.726324
---> x = 101819 + 0.726324
---> x = 101819 · 100.726324
My calculator give me the value of 5.325 for 100.726324
So, the answer is approximately 5.325 x 101819
8 is not that far from 10. So it isn't unlikely that 82015 has at least more than 1000 digits. Thus I use Wolfram Alpha to calculate this:
82015 ≈ 5.33 * 101819.
Guess I was right ;)
To get an approximate answer, use logs:
x = 82015
---> log(x) = log(82015)
Since exponents in logs come out as multipliers:
---> log(x) = 2015·log(8) ≈ 1819.726
Find the antilog:
---> x = 101819.726324
---> x = 101819 + 0.726324
---> x = 101819 · 100.726324
My calculator give me the value of 5.325 for 100.726324
So, the answer is approximately 5.325 x 101819