what is dy/dx when e^xy=x+y?

e^xy  = x + y    

Using implicit differentiation, we have

ye^xy + xy'e^xy  = 1 + y'

y' ( xe^xy - 1) = 1 - ye^xy

y' = [ 1 - ye^xy  ] / [ xe^xy - 1]  

Thanks Chris,

I really need practice at these so it is great when they come onto the forum.

I even got the same answer as you - isn't that great :)

Thanks anon for giving us this question :)