+839 What is the length of the sides of a rhombus whose diagonals are 40 and 96?
+576 In a rhombus each diagonal bisects the other to form 4 right triangles. The side lengths of these triangles will be half the diagonal lengths since the diagonals were bisected. This leaves us triangles with side lengths of 20 and 48 with the hypotenuse being a side length of the rhombus. Apply the pythagorean theorem:
20^2+48+2=h^2
400+2304=h^2
2704=h^2
sqrt(2704)=h
52=h
+576 In a rhombus each diagonal bisects the other to form 4 right triangles. The side lengths of these triangles will be half the diagonal lengths since the diagonals were bisected. This leaves us triangles with side lengths of 20 and 48 with the hypotenuse being a side length of the rhombus. Apply the pythagorean theorem:
20^2+48+2=h^2
400+2304=h^2
2704=h^2
sqrt(2704)=h
52=h
