What is the length of the sides of a rhombus whose diagonals are 40 and 96?

Rose98 Jul 8, 2014

#2**+13 **

In a rhombus each diagonal bisects the other to form 4 right triangles. The side lengths of these triangles will be half the diagonal lengths since the diagonals were bisected. This leaves us triangles with side lengths of 20 and 48 with the hypotenuse being a side length of the rhombus. Apply the pythagorean theorem:

20^2+48+2=h^2

400+2304=h^2

2704=h^2

sqrt(2704)=h

52=h

jboy314 Jul 8, 2014

#2**+13 **

Best Answer

In a rhombus each diagonal bisects the other to form 4 right triangles. The side lengths of these triangles will be half the diagonal lengths since the diagonals were bisected. This leaves us triangles with side lengths of 20 and 48 with the hypotenuse being a side length of the rhombus. Apply the pythagorean theorem:

20^2+48+2=h^2

400+2304=h^2

2704=h^2

sqrt(2704)=h

52=h

jboy314 Jul 8, 2014