What is the absolute value for |10p-4| < 34 ?
\(| 10p-4 |<34 \)
\(| p | <\frac{34+4}{10}\)
\(| p | < 3.8\)
\(L = \{| p | \in \mathbb| \mathbb R | <3.8\}\)
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We will actually have an open interval solution here that will lie between two values
l 10p - 4 l < 34 set the equation equal
l 10p - 4 l = 34
This says that
10p - 4 = 34 and 10p - 4 = -34
add 4 to both sides
10p = 38 10p = -30
divide both sides by 10
p = 3.8 p = - 3
The solutions will occur between these two values....so -3 < p < 3.8