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what is the angle of a triangle that has a 45 length hypotenuse and 24 length adjacent leg?

 Apr 30, 2014

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 #1
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the cosine is the ratio of the adjacent leg of it's angle to the hypotenuse

$$\cos(\theta)=\dfrac {24}{45}$$

$$\theta = \arccos\left(\dfrac{24}{45}\right)$$

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{24}}}{{\mathtt{45}}}}\right)} = {\mathtt{57.769\: \!047\: \!364\: \!498^{\circ}}}$$

 Apr 30, 2014
 #1
avatar+6251 
+5
Best Answer

the cosine is the ratio of the adjacent leg of it's angle to the hypotenuse

$$\cos(\theta)=\dfrac {24}{45}$$

$$\theta = \arccos\left(\dfrac{24}{45}\right)$$

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{24}}}{{\mathtt{45}}}}\right)} = {\mathtt{57.769\: \!047\: \!364\: \!498^{\circ}}}$$

Rom Apr 30, 2014

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