What is the answer to (3x+5)(3x-5)? I know it is simple but I can't seem to get it, and unfortunatly I lost my math book. Please help!
+118613 You cannot solve it Tenacious because there is no equal sign :)
The asker want to expand and simplify it.
(3x+5)(3x-5)
you can expand it the long way but you should learn to recognise this as the difference of 2 squares.
The brakets are the same but one has a minus and the other a plus. (Thay are a conjugate pair)
the answer will be $$(3x)^2-5^2=9x^2-25$$
+226 Firstly, are you trying to expand these brackets or solve this for x?
+118613 You cannot solve it Tenacious because there is no equal sign :)
The asker want to expand and simplify it.
(3x+5)(3x-5)
you can expand it the long way but you should learn to recognise this as the difference of 2 squares.
The brakets are the same but one has a minus and the other a plus. (Thay are a conjugate pair)
the answer will be $$(3x)^2-5^2=9x^2-25$$
+226 Yes, unsolvable for x as it is, I was hoping for more information if they replied.
(3x+5)(3x-5) If I expand this I get;
3x2-15x+15x-25
3x2-25 How you have got to your answer, I have no idea.
I have heard the term "difference of two squares" but that's my only exposure to it.
+118613 It is not $$3x^2$$
it is $$(3x)^2=3x*3x=9x^2$$
Difference of 2 squares $$\boxed{a^2-b^2=(a-b)(a+b)}$$
It is difference because it is subtraction.
Here are some for you
$$\\simplify\\
1) (a+3)(a-3)\\
2) (2n-4)(2n+4)\\
3) (5-2t)(5+2t)\\\\\\
factorize\\
4)\;\; x^2-16\\
5) \;\;9-4m^2\\
6)\;\;16x^2-a^2b^2$$
+226 I don't really understand this at the moment and haven't got the time to get my head into it so I'll have to come back to it and the other factorising questions you set on the other post in a few days. I'll message you when I've done them rather than you having to check. Thanks for the challenges.
