Solve the following system:
{3 x+y = -1 | (equation 1)
y-3 x = 5 | (equation 2)
Add equation 1 to equation 2:
{3 x+y = -1 | (equation 1)
0 x+2 y = 4 | (equation 2)
Divide equation 2 by 2:
{3 x+y = -1 | (equation 1)
0 x+y = 2 | (equation 2)
Subtract equation 2 from equation 1:
{3 x+0 y = -3 | (equation 1)
0 x+y = 2 | (equation 2)
Divide equation 1 by 3:
{x+0 y = -1 | (equation 1)
0 x+y = 2 | (equation 2)
Collect results:
Answer: |x = -1 and y=2
