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What is the area of the two-dimensional cross section that is parallel to face ABC ?

 

Enter your answer in the box.

 

 ? ft²

 Jun 4, 2019
edited by jiminblossoms  Jun 4, 2019

Best Answer 

 #1
avatar+1068 
-1

The two-dimensional cross-section that is parallel to face ABC is just the triangle ABC.

We need to find the area of ABC.

Since it is a right triangle, we can use the Pythagorean theorem.

5^2+x^2=13^2

25+x^2=169

x^2=144

x=12

Therefore, the area of ABC is 5*12/2=30 ft^2.

 

You are very welcome!

:P

 Jun 4, 2019
 #1
avatar+1068 
-1
Best Answer

The two-dimensional cross-section that is parallel to face ABC is just the triangle ABC.

We need to find the area of ABC.

Since it is a right triangle, we can use the Pythagorean theorem.

5^2+x^2=13^2

25+x^2=169

x^2=144

x=12

Therefore, the area of ABC is 5*12/2=30 ft^2.

 

You are very welcome!

:P

CoolStuffYT Jun 4, 2019
 #2
avatar+39 
0

The area of the two-dimensional cross section that is parallel to face ABC.that is Area of Δ DEF = 84 ft²

Step-by-step explanation: 

Given : A triangular prism with some side measurement.

We have  to find the area of the two-dimensional cross section that is parallel to face ABC.


Since, the cross section that is parallel to face ABC.

Since, face parallel to ABC is DEF .

And DEF is a triangle with ∠ E = 90°

So, Area of right angled triangle is 1/2 times base times height.

Base = 24 ft 

and height is 7 ft 

So, Area of Δ DEF = 1/2 times 24 times 7

Simplify , we have, 

Area of Δ DEF = 84 ft²

Thus, The area of the two-dimensional cross section that is parallel to face ABC.that is Area of Δ DEF = 84 ft²


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