nCr(7,4)
$${\left({\frac{{\mathtt{7}}{!}}{{\mathtt{4}}{!}{\mathtt{\,\times\,}}({\mathtt{7}}{\mathtt{\,-\,}}{\mathtt{4}}){!}}}\right)} = {\mathtt{35}}$$
what is the awenswer to this math problem 7C 4
what is the awenswer to this math problem 7C 3
$$\small{\text{$7C4 = 7C3 = \dbinom74 = \dbinom73= 35 $}}$$
$${\mathtt{7}}{\mathtt{\,\times\,}}{{\mathtt{16}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{{\mathtt{16}}}^{{\mathtt{1}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}}{\mathtt{\,\times\,}}{{\mathtt{16}}}^{{\mathtt{0}}} = {\mathtt{1\,988}}$$