What is the circumradius of a triangle ABC with sides of length 6,8,and 10?
+23252 The circumcenter of a right triangle occurs at the midpoint of the hypotenuse.
The radius of the circumcircle will be the distance from the midpoint to either end of the hypotenuse;
in this case, the radius is 5.
Right scalene Pythagorean triangle.
Sides: a = 6 b = 8 c = 10
Area: T = 24
Perimeter: p = 24
Semiperimeter: s = 12
Circumradius(R)
The circumcircle of a triangle is a circle that passes through all of the triangle's vertices, and the circumradius of a triangle is the radius of the triangle's circumcircle. Circumcenter (center of circumcircle) is the point where the perpendicular bisectors of a triangle intersect.
R=(abc) / 4rs =6.8.10 / 4.2.12 =5
What is the circumradius of a triangle ABC with sides of length 6,8,and 10?
We recognize that a 6, 8, 10 triangle is a right triangle. 62 + 82 = 102
Since it's a right triangle, the hypotenuse is the diameter of the circle it's inscribed in.
The radius is half the diameter, so .... radius = 5
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