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what is the derivative of f(x)= ((f(x)-sqrt(x))/5)

Guest Sep 15, 2014

Best Answer 

 #1
avatar+92781 
+10

$$\\f(x)=\frac{f(x)-\sqrt x}{5}\\\\
5f(x)=f(x)-\sqrt x\\\\
4f(x)=-\sqrt x\\\\
f(x)=\dfrac{-x^{0.5}}{4}\\\\
f'(x)=\dfrac{-0.5x^{-0.5}}{4}\\\\
f'(x)=\dfrac{-0.5}{4\sqrt{x}}\\\\
f'(x)=\dfrac{-1}{8\sqrt{x}}\\\\$$

 

I think that is what you wanted.  

Melody  Sep 15, 2014
 #1
avatar+92781 
+10
Best Answer

$$\\f(x)=\frac{f(x)-\sqrt x}{5}\\\\
5f(x)=f(x)-\sqrt x\\\\
4f(x)=-\sqrt x\\\\
f(x)=\dfrac{-x^{0.5}}{4}\\\\
f'(x)=\dfrac{-0.5x^{-0.5}}{4}\\\\
f'(x)=\dfrac{-0.5}{4\sqrt{x}}\\\\
f'(x)=\dfrac{-1}{8\sqrt{x}}\\\\$$

 

I think that is what you wanted.  

Melody  Sep 15, 2014
 #2
avatar+87301 
0

Nice one, Melody.....!!!

 

CPhill  Sep 15, 2014
 #3
avatar+92781 
0

Thanks Chris.   

Melody  Sep 15, 2014

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