+0  
 
0
192
1
avatar+22 

What is the domain of the real-valued function: \(q(x) = \frac{\sqrt{x}}{\sqrt{1-x^2}}\)Express your answer as an interval or as a union of intervals.

 Mar 8, 2019
 #1
avatar+106533 
+1

We have a couple of things to consider

 

First.....the domain of the function ih the numerator is  x ≥ 0

 

For the  function in the denominator.....1 - x^2  must be greater than 0

 

So

 

1 - x^2 > 0

 

( 1 - x) ( 1 + x ) >  0

 

If     -1 < x < 1     this is true

 

But....the restriction in the denominator makes the true domain   0  ≤ x < 1

 

 

cool cool cool

 Mar 8, 2019

25 Online Users