What is the domain of the real-valued function: \(q(x) = \frac{\sqrt{x}}{\sqrt{1-x^2}}\)Express your answer as an interval or as a union of intervals.

alcumus Mar 8, 2019

#1**+1 **

We have a couple of things to consider

First.....the domain of the function ih the numerator is x ≥ 0

For the function in the denominator.....1 - x^2 must be greater than 0

So

1 - x^2 > 0

( 1 - x) ( 1 + x ) > 0

If -1 < x < 1 this is true

But....the restriction in the denominator makes the true domain 0 ≤ x < 1

CPhill Mar 8, 2019