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What is the equation of a line that passes through the point (8, 1) and is perpendicular to the line whose equation isy=−23x+5y=−23x+5 ?

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Johnnyboy  Dec 11, 2017
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y = -23x  +  5

 

The slope of a perpendicular line to this is  (1/23)

 

So....the equation of this line passing through (8,1) is

 

y =  (1/23) (x - 8)  + 1

 

y = (1/23)x - 8/23 + 1

 

y = (1/23)x - 8/23 + 23/23

 

y = (1/23)x + 15/23

 

 

cool cool cool

CPhill  Dec 11, 2017

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