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What is the exact value of the exponential equation 17+e7x=33 ?
b. x=ln16 /33
c. x=ln16 /7

 

 

 

thank you 

 Jan 16, 2019
 #1
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17 + e^(7x) = 33     subtract 17 from both sides

 

e^(7x)  =  16           take the Ln of both sides

 

Ln e^(7x)  = Ln 16      and we can write

 

(7x) Ln e  = Ln 16         Ln e = 1.....so we  can ignore this

 

7x =  Ln 16         divide both sides by 7

 

x =  [ Ln 16 ]  / 7

 

 

 

cool cool cool

 Jan 16, 2019

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