What is the exact value of the exponential equation 17+e7x=33 ? b. x=ln16 /33 c. x=ln16 /7
thank you
17 + e^(7x) = 33 subtract 17 from both sides
e^(7x) = 16 take the Ln of both sides
Ln e^(7x) = Ln 16 and we can write
(7x) Ln e = Ln 16 Ln e = 1.....so we can ignore this
7x = Ln 16 divide both sides by 7
x = [ Ln 16 ] / 7