What is the exact value of x in the exponential equation 3.2 + e6x = 54.2?
A.) x=in51/6
b.) x=in 16.9/6
c.) x= in 51-6
d.) x= in51/in 6
I think this isupposed to be:
3.2 + e^(6x) = 54.2 subtract 3.2 from both sides
e^(6x) = 51 take the Ln of both sides
Ln e^(6x) = Ln (51) and we can write
(6x) Ln e = Ln (51) and Ln e = 1, so we can ignore this....so....
6x = Ln (51) divide both sides by 6
x = Ln ( 51) / 6