What is the formula to find the area of a rhombus?

Here's another - albeit, more exotic - way of determining the area of a rhombus.......

Given rhombus BCDE, let BK be the altitude of triangle BDE. And the area of BDE = (1/2)DE * BK. And by the same token, let OD be the altitude of triangle BCD. And the area of BCD = (1/2) BC *OD.  And OD = BK.......and let these be = h, the height of the rhombus. And DE = BC. So, the total area of the rhombus = (1/2)h (DE + DE) = h*(1/2)*2DE =  h * one side of the rhombus.

And we have triangle EHD with base ED and altitude HR. And HR is a radius of the circle with a center of H inscribed in the rhombus. And we have three more triangles, BHE, BHC and CHD with the same radius as an altitude and a side of the rhombus as a base. And since all the sides of the rhombus are the same, then the total area is just (1/2)(4DE)*r = 2DE * r = DE* 2r  =  the side of the rhombus * the diameter of a circle inscribed in the rhombus

This implies that

[h * one side of the rhombus]  = [one side of the rhombus * the diameter of a circle inscribed in the rhombus]

Which further implies that  the height of the rhombus = the diameter of a circle inscribed in the rhombus.

Area = (1/2) d₁ * d₂     ...  where d₁ and d₂ are the diagonals

I was doing my research and I found out you could do base * height to make it easier.