\begin {tabular} {|c|c|c|c|c|c|}\hline $x$&-2&-1&0&1&2\\\hline $f(x)$&9&4&-1&-6&-11\\\hline \end {tabular}
f(x)=-5x-1
I'll try and give you an insight into some of my logic.
When the top is positive, the bottom is negative so there is a mult by a neg number in there.
Then I just looked at the numbers and "times by -5" came to me as a distinct possibility,
the nubers would have been 10,5,0,-5,-10
so I had to subtract 1
\begin {tabular} {|c|c|c|c|c|c|}\hline $x$&-2&-1&0&1&2\\\hline $f(x)$&9&4&-1&-6&-11\\\hline \end {tabular}
f(x)=-5x-1
I'll try and give you an insight into some of my logic.
When the top is positive, the bottom is negative so there is a mult by a neg number in there.
Then I just looked at the numbers and "times by -5" came to me as a distinct possibility,
the nubers would have been 10,5,0,-5,-10
so I had to subtract 1