What is the largest integer value of m such that the equation 3x^2 - mx + 21 = 0 has no real solutions?

Guest Feb 3, 2022

#1**0 **

Hint: For b² - 4ac < 0 it has no real solutions,

then a = 3, b = -m and c = 7.

Straight Feb 3, 2022

#3**0 **

my bad.

so (- m)^{2} - 4 * 3 * 21 < 0 calculate

m^{2} - 252 < 0 + 252

m^{2} < 252 sqrt both sides

m < 15.87... round to the nearest integer (16)

m = 16

16 is the answer.

Straight Feb 3, 2022

#4**+1 **

m < 15.87...

Actually, m = 15 is the largest integer value of m such that the equation 3x^2 - mx + 21 = 0 has no real solutions.

ElectricPavlov
Feb 4, 2022