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What is the maximum possible value of the greatest common divisor of two consecutive terms of the sequence \(a_n = n! + n\), where \(n \ge 0\)?

 Mar 6, 2020
 #1
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GCD = 1

 Mar 7, 2020
 #2
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With the possible exception of 1 and 2, which give: 1!+1=2 and 2! + 2 =4, where GCD =2, the gcd of all other terms of sequence will be = 1

 Mar 7, 2020

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