What is the maximum possible value of the greatest common divisor of two consecutive terms of the sequence \(a_n = n! + n\), where \(n \ge 0\)?
GCD = 1
With the possible exception of 1 and 2, which give: 1!+1=2 and 2! + 2 =4, where GCD =2, the gcd of all other terms of sequence will be = 1
