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what is the of the line that passes through the points (-2,1) and (4,5) in the cartesian coordinate plane?

 Aug 24, 2015

Best Answer 

 #1
avatar+128474 
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(-2,1) and (4,5)....let's get the slope, first

 

First, subtract the y coordinates in any order  [ 5 - 1]  = 4

Next, subtract the x coordinates in the same order  [4 - (-2)]  = [4 + 2] = 6

Put the first thing over the second → 4/6  = 2/3    and this is the slope

 

Now....just choose  one point [I'll use (4,5)]    and set up the following "formula".....

 

y - [y coordinate of our point] - (slope)* [ x - ( the  x coordinate of our point)]

 

Let's fill in the "blanks"

 

y - 5  = (2/3)(x - 4)      add 5 to both sides

 

y = (2/3)(x - 4) + 5   and this is the equation of the line in "slope-intercept" form

 

Here's the graph...... https://www.desmos.com/calculator/rc6dclpaqg

 

 

 Aug 24, 2015
 #1
avatar+128474 
+5
Best Answer

(-2,1) and (4,5)....let's get the slope, first

 

First, subtract the y coordinates in any order  [ 5 - 1]  = 4

Next, subtract the x coordinates in the same order  [4 - (-2)]  = [4 + 2] = 6

Put the first thing over the second → 4/6  = 2/3    and this is the slope

 

Now....just choose  one point [I'll use (4,5)]    and set up the following "formula".....

 

y - [y coordinate of our point] - (slope)* [ x - ( the  x coordinate of our point)]

 

Let's fill in the "blanks"

 

y - 5  = (2/3)(x - 4)      add 5 to both sides

 

y = (2/3)(x - 4) + 5   and this is the equation of the line in "slope-intercept" form

 

Here's the graph...... https://www.desmos.com/calculator/rc6dclpaqg

 

 

CPhill Aug 24, 2015

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