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What is the perimeter of a regular hexagon that has an area of 93.53?

Guest Apr 13, 2015

Best Answer 

 #1
avatar+17746 
+5

A regular hexagon is made up of 6 equilateral triangles.

The area of each equilateral triangle is 93.52  ÷  6  =  15.58666...

The formula for the area of an equilateral triangle is √3/4·s2

--->   √3/4·s2  =  15.586....    (multiply by 4 and divide by √3)

--->   s2  =  36

--->   s  =  6

geno3141  Apr 14, 2015
 #1
avatar+17746 
+5
Best Answer

A regular hexagon is made up of 6 equilateral triangles.

The area of each equilateral triangle is 93.52  ÷  6  =  15.58666...

The formula for the area of an equilateral triangle is √3/4·s2

--->   √3/4·s2  =  15.586....    (multiply by 4 and divide by √3)

--->   s2  =  36

--->   s  =  6

geno3141  Apr 14, 2015

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