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what is the points of y=2x-3 y=-3x+2

 Dec 10, 2014

Best Answer 

 #2
avatar+752 
+5

$$\underset{\,\,\,\,{\textcolor[rgb]{0.66,0.66,0.66}{\rightarrow {\mathtt{y, x}}}}}{{solve}}{\left(\begin{array}{l}{\mathtt{y}}={\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{3}}\\
{\mathtt{y}}={\mathtt{\,-\,}}{\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}\\
{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{3}}={\mathtt{\,-\,}}{\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}\\
{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{x}}={\mathtt{2}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}}\\
{\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{x}}={\mathtt{5}}\\
{\mathtt{x}}={\mathtt{1}}\end{array}\right)}$$

.
 Dec 10, 2014
 #1
avatar+33616 
+5

If y = 2x - 3 and y = -3x + 2 then:

2x - 3 = -3x + 2

 

Add 3x to both sides:

5x - 3 = 2

 

Add 3 to both sides

5x = 5

 

Divide both sides by 5

x = 1

 

Put this value back into y = 2x - 3 to get

y = 2*1 - 3

or y = -1

.

 Dec 10, 2014
 #2
avatar+752 
+5
Best Answer

$$\underset{\,\,\,\,{\textcolor[rgb]{0.66,0.66,0.66}{\rightarrow {\mathtt{y, x}}}}}{{solve}}{\left(\begin{array}{l}{\mathtt{y}}={\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{3}}\\
{\mathtt{y}}={\mathtt{\,-\,}}{\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}\\
{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{3}}={\mathtt{\,-\,}}{\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}\\
{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{x}}={\mathtt{2}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}}\\
{\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{x}}={\mathtt{5}}\\
{\mathtt{x}}={\mathtt{1}}\end{array}\right)}$$

Sasini Dec 10, 2014
 #3
avatar+118609 
0

Thanks Sasini but where is the y solution?

 Dec 11, 2014

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