b. Alice’s school is selling tickets to the school carnival.

On the first day of ticket sales, the school sold 3 adult tickets and 9 student tickets for a total of $75.

The second day, the school sold $67 by selling 8 adult and 5 student tickets.

What is the price each of one adult and one student ticket?

Guest Mar 12, 2019

#1**+2 **

Let x = Adult price

Let y = student price

Then you have the following system of equations:

3x + 9y = $ 75 and

8x + 5y = 67 Now solve....

SInce 3x + 9y = 75 if we divide through by 3

x+3y = 25 re-arrange

x = 25 -3y Sustitute THIS value of 'x' in to the second equation of the set

8 (25-3y) + 5y = 67 and solve for y

200 - 24 y + 5y = 67

-19y = -133

y = student price = $ 7

NOW, substitue THIS value of y into either one of the first two equations to calculate x ...the adult price...

,,,,,,,,.you should be able to finish,,,

ElectricPavlov Mar 12, 2019

#1**+2 **

Best Answer

Let x = Adult price

Let y = student price

Then you have the following system of equations:

3x + 9y = $ 75 and

8x + 5y = 67 Now solve....

SInce 3x + 9y = 75 if we divide through by 3

x+3y = 25 re-arrange

x = 25 -3y Sustitute THIS value of 'x' in to the second equation of the set

8 (25-3y) + 5y = 67 and solve for y

200 - 24 y + 5y = 67

-19y = -133

y = student price = $ 7

NOW, substitue THIS value of y into either one of the first two equations to calculate x ...the adult price...

,,,,,,,,.you should be able to finish,,,

ElectricPavlov Mar 12, 2019