What is the probability that Fatima gets fewer heads than tails if she flips 10 coins?
The prob of gettint exactly 5 heads is 10C5 (0.5)^10 = 252/1024 = 63/256
So it seems logical that the prob of not getting 5 heads is 1-63/256 = 193/256
and hall of those would have fewer heads than tails
(193/256) /2 = 193/512
This is the correct answer which can be seen by evaluating
\(\sum \limits_{k=0}^4~\dbinom{10}{k}\left(\dfrac 1 2\right)^{10}= \dfrac{193}{512}\)
