What is the product of 3.15 m and 2.006 m with the correct number of significant figures?

6 m^{2}

6.3 m^{2}

6.32 m^{2}

6.319 m^{2}

i think its A ? 6?

The answer would be C. 6.32 m^2

Hope this Helps ;P

why is that?

Thank you for yuor help!

When you multiply two numbers, the number of significant figures is the least number of decimal places. In this case, that is 2 (3.15 has 2 decimal places). Rounding 6.319 to two decimal places, you get 6.32

Hope that clarified things

Thank you so much ! Makes sense