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What is the product of all possible digits \(x\) such that the six-digit number \(341,4x7\) is divisible by 3?

 Oct 13, 2020
 #1
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To be divisible by three the sum of all of the digits has to be divisible by 3 also

 

3+4+1+4+x+7 = 19+x        if x = 2 5 8    it will be divisible by 3  

   you can finish the Q.........

 
 Oct 13, 2020
 #2
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i don't know where to start

 
Guest Oct 13, 2020
 #3
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x=2 and x = 5 and x = 8

 

341,427 mod 3 = 0

341457 mod 3 = 0

341487 mod 3 = 0

Product =2 x 5 x 8 = 80

 
Guest Oct 13, 2020
 #4
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Thank You!!!

 
Guest Oct 13, 2020

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