What is the product of all possible digits \(x\) such that the six-digit number \(341,4x7\) is divisible by 3?
+37146 To be divisible by three the sum of all of the digits has to be divisible by 3 also
3+4+1+4+x+7 = 19+x if x = 2 5 8 it will be divisible by 3
you can finish the Q.........
