What is the slope of the line that is tangent to a circle at point (5,5) if the center of the circle is (3,2)? Express your answer as a common fraction.
This line will be perpendicular to the radial line drawn from the center to (5,5)
And the slope of this radial line is [ 5 - 2 ] / [5 - 3 ] = 3/2
And the slope of the line perpendicular to this will be the negative reciprocal
= - 2/3
+489 
