What is the slope of the line that is tangent to a circle at point (5,5) if the center of the circle is (3,2)? Express your answer as a common fraction.

Guest Mar 29, 2020

#1**+1 **

Slope from center to point 5-2 / 5-3 = 3/2 perpindicular slope = -1 / 3/2 = - 2/3

ElectricPavlov Mar 29, 2020

#2**+1 **

Hint: The angle formed by a tangent line and the circle's radius when is a 90 degree angle

Using this info, can you find the slope?

Another hint: The slopes of perpendicular lines are negative reciprocals of each other.

Example of a negative reciprocal:

\(2\) and \(-\frac{1}{2}\)

AnExtremelyLongName Mar 29, 2020