What is the slope of the line that is tangent to a circle at point (5,5) if the center of the circle is (3,2)? Express your answer as a common fraction.
+37146 Slope from center to point 5-2 / 5-3 = 3/2 perpindicular slope = -1 / 3/2 = - 2/3
+658 Hint: The angle formed by a tangent line and the circle's radius when is a 90 degree angle
Using this info, can you find the slope?
Another hint: The slopes of perpendicular lines are negative reciprocals of each other.
Example of a negative reciprocal:
\(2\) and \(-\frac{1}{2}\)
