#2**+8 **

**What is the slope of the line through the points (-2, -5) and (1, -7)**

The formula of a line is** y=mx+b**

and **m** is the slop.

We have point 1 with x = -2 and y = -5 ... so we have -5 = m*(-2) + b or **-5 = -2m+b**

We have point 2 with x = 1 and y = -7... so we have -7 = m*(1) + b or **-7= m+b**

Now we subtract the equation 2 of the equation 1:** -7 -(-5) = m+b - (-2m+b)**

so we have **-7+5 = m+b+2m-b**

or ** -2 = 3m**

and the slope m is $$\small{\text{$-\dfrac{2}{3}$}}$$

heureka
Jun 19, 2015

#1**+8 **

To get the slope......subtract the y components of each point in any order....then......subtract the x components in the same order.....put the first result over the second.....so we have.....

-7 - (-5) = -2

Subtract the x components in the same order......

1 - (-2) = 3

Put the first result over the second........-2/3 ..... and that's the slope....!!!!

CPhill
Jun 18, 2015

#2**+8 **

Best Answer

**What is the slope of the line through the points (-2, -5) and (1, -7)**

The formula of a line is** y=mx+b**

and **m** is the slop.

We have point 1 with x = -2 and y = -5 ... so we have -5 = m*(-2) + b or **-5 = -2m+b**

We have point 2 with x = 1 and y = -7... so we have -7 = m*(1) + b or **-7= m+b**

Now we subtract the equation 2 of the equation 1:** -7 -(-5) = m+b - (-2m+b)**

so we have **-7+5 = m+b+2m-b**

or ** -2 = 3m**

and the slope m is $$\small{\text{$-\dfrac{2}{3}$}}$$

heureka
Jun 19, 2015