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What is the smallest number that can be divided by 5, 7 and 11, leaving a remainder of 4 in each case?

 Aug 7, 2015

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 #1
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What is the smallest number that can be divided by 5, 7 and 11, leaving a remainder of 4 in each case?

 

$$x= 4+z\cdot 385 \qquad z \in Z$$

 

 Aug 7, 2015
 #1
avatar+25325 
+10
Best Answer

What is the smallest number that can be divided by 5, 7 and 11, leaving a remainder of 4 in each case?

 

$$x= 4+z\cdot 385 \qquad z \in Z$$

 

heureka Aug 7, 2015

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