What is the smallest number that can be divided by 5, 7 and 11, leaving a remainder of 4 in each case?

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Guest Aug 7, 2015

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What is the smallest number that can be divided by 5, 7 and 11, leaving a remainder of 4 in each case?

$x= 4+z\cdot 385 \qquad z \in Z$

heureka Aug 7, 2015

heureka · Answer 1 · 2015-08-07T06:48:09

What is the smallest number that can be divided by 5, 7 and 11, leaving a remainder of 4 in each case?

$x= 4+z\cdot 385 \qquad z \in Z$