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What is the smallest number that can be divided by 5, 7 and 11, leaving a remainder of 4 in each case?

Guest Aug 7, 2015

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What is the smallest number that can be divided by 5, 7 and 11, leaving a remainder of 4 in each case?

 

$$x= 4+z\cdot 385 \qquad z \in Z$$

 

heureka  Aug 7, 2015
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1+0 Answers

 #1
avatar+18715 
+10
Best Answer

What is the smallest number that can be divided by 5, 7 and 11, leaving a remainder of 4 in each case?

 

$$x= 4+z\cdot 385 \qquad z \in Z$$

 

heureka  Aug 7, 2015

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