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what is the square root of  252 in simplest radical form?

 Mar 8, 2021
 #1
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252's prime factorization is \(2^2 * 61\). Looking at this, there are 2 twos, so you can take one out of the equation and get \(2*\sqrt61\)

 Mar 8, 2021
 #2
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Panda, it's 63 not 61.  Please correct your answer if it isn't too late. 

Guest Mar 8, 2021
 #3
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Okay, if you won't do it, I will. 

 

You can factor 252 to 36 • 7   

 

So sqrt(252)  =  6 • sqrt(7)  

Guest Mar 9, 2021

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