what is the square root of 252 in simplest radical form?
252's prime factorization is \(2^2 * 61\). Looking at this, there are 2 twos, so you can take one out of the equation and get \(2*\sqrt61\)
Panda, it's 63 not 61. Please correct your answer if it isn't too late.
Okay, if you won't do it, I will.
You can factor 252 to 36 • 7
So sqrt(252) = 6 • sqrt(7)
+31 
