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What is the value of the leading coefficient a, if the polynomial function P(x) = a(x + b)^2(x − c) has a multiplicity of 2 at the point (−1, 0) and also passes through the points (7, 0) and (0, −14)?

 Feb 22, 2016
 #1
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If a function has a root at the value  x = a, it will have a factor of  x - a.  

 

If a function has a root at the point (-1,0), the x-value is -1, so the factor is  x - -1  = x + 1.

If it has two roots at that point (multiplicity two), it will have the factor  x + 1 twice, or  (x + 1)2.

 

If it passes through the point (7, 0), x = 7, so it has a factor of x - 7.

 

Thus the function is  y  =  a(x + 1)2(x - 7)

 

Since it passes through the point (0,-14), replace  y  with  -14 and  x  with  0.

--->   -14  =  a(0 + 1)2(0 - 7)   --->   -14  =  a(1)2(-7)   --->   -14  =  a(-7)   --->   a  =  2

 

So the function is:  y  =  2(x + 1)2(x - 7)

 Feb 22, 2016
 #2
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Are you wanting us to answer all of the questions on your worksheet?

 Feb 22, 2016

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