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what is the volume and surface area of a truncated cube

Guest May 25, 2014

Best Answer 

 #9
avatar+93654 
+10

that is really interesting.

Here is a truncated cube

It has 14 faces.  6 regular octogons and  8 equilateral triangles.  

I LIKE IT!!!

Melody  May 26, 2014
 #1
avatar+8 
+5

Area and volume

The area A and the volume V of a truncated cube of edge length are:

A = 2\left(6+6\sqrt{2}+\sqrt{3}\right)a^2 \approx 32.4346644a^2
V = \frac{1}{3}\left(21+14\sqrt{2}\right)a^3 \approx 13.5996633a^3.
Aychik  May 25, 2014
 #2
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0

What is a truncated cube?  Is that a proper term?

Melody  May 25, 2014
 #3
avatar+27042 
+5

A truncated cube is one with the corners lopped off.

Alan  May 25, 2014
 #4
avatar+93654 
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How much of the corners?

Melody  May 25, 2014
 #5
avatar+27042 
+5

Have a look at http://en.wikipedia.org/wiki/Truncated_cube for the details.

Alan  May 25, 2014
 #6
avatar+93654 
0

Thank you Alan.  I was just being lazy!

Is that first answer correct?  I'll tick it if it is.

Melody  May 25, 2014
 #7
avatar+27042 
+5

The first answer is correct (copied directly from Wikipedia by the looks of it).

Alan  May 25, 2014
 #8
avatar+93654 
0

Thank you Alan.

Melody  May 25, 2014
 #9
avatar+93654 
+10
Best Answer

that is really interesting.

Here is a truncated cube

It has 14 faces.  6 regular octogons and  8 equilateral triangles.  

I LIKE IT!!!

Melody  May 26, 2014

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