+0  
 
0
639
1
avatar
Hi, I needhelp to find this solution, cause i dont know.. Amplitude and frequenc and midpoint line y in 2y=cos(8t-6))+4 :'(
 Mar 22, 2014
 #1
avatar+6251 
0
Quote:

Hi, I needhelp to find this solution, cause i dont know.. Amplitude and frequenc and midpoint line y in 2y=cos(8t-6))+4 :'(



2y=cos(8t-6)+4

y = 1/2 cos(8t-6)+2

The amplitude is the coefficient of the cosine term or A = 1/2

The frequency is the coefficient of the t term in the argument to the cosine divided by 2pi, or freq = 8/(2pi) = 4/pi.

I guess by midpoint line you mean the line that corresponds to the cosine term being equal to 0 and this is given by the offset that's added to the cosine term, i.e.

y = 2
 Mar 22, 2014

2 Online Users

avatar